Respuesta :

Using trigonometric ratio

[tex]\begin{gathered} \cos x^{\circ}=\frac{adjacent}{\text{hypotenuse}} \\ \text{cosx}=\frac{5}{8} \\ \cos x=0.625 \\ x=\cos ^{-1}0.625 \\ x=51.3178125465 \\ x=51^{\circ} \end{gathered}[/tex]