To solve this question, we have to convert the grams of glucose to moles using its molecular weigth and convert the grams of water to kilograms of water using a conversion factor:
[tex]110gGlucose\cdot\frac{1molGlucose}{180.16gGlucose}=0.61molGlucose[/tex][tex]500gH_2O\cdot\frac{1kg}{1000g}=0.5kgH_2O[/tex]Now, divide the number of moles of glucose by the number of kg of water to find the molality of the solution:
[tex]m=\frac{0.61mol}{0.5kg}=1.22m[/tex]