Enter an equation in point-slope form for the line.(7,6) and (8,3) is on the line.

First, we will calculate the slope of the line
[tex]m=\frac{3-6}{8-7}[/tex][tex]m=\frac{3}{1}\rightarrow m=-3[/tex]Now let's calculate the y-axis crossing
[tex]b=y-mx[/tex][tex]b=6+3\cdot7[/tex][tex]b=6+21[/tex][tex]b=27[/tex]The equation would be: y = 3x - 15
[tex]b=y-mx[/tex][tex]b=3+3\cdot8[/tex][tex]b=27[/tex][tex]y=-3x+27[/tex]