In order to determine the required force to stop the car, proceed as follow:
Calculate the deceleration of the car, by using the following formula:
[tex]v^2=v^2_o-2ax[/tex]where,
v: final speed = 0m/s (the car stops)
vo: initial speed = 36m/s
x: distance traveled = 980m
a: deceleration of the car= ?
Solve the equation above for a, replace the values of the other parameters and simplify:
[tex]\begin{gathered} a=\frac{v^2_o-v^2}{2x} \\ a=\frac{(36\frac{m}{s})^2-(0\frac{m}{s})^2}{2(980m)}=0.66\frac{m}{s^2} \end{gathered}[/tex]Next, consider that the formula for the force is:
[tex]F=ma[/tex]where,
m: mass of the car = 820 kg
a: deceleration of the car = 0.66m/s^2
Replace the previous values and simplify:
[tex]F=(820kg)(0.66\frac{m}{s^2})=542.20N[/tex]Hence, the required force to stop the car is 542.20N