SOLUTION:
Step 1:
In this question, we are meant to determine the length of x in the triangle.
We are also expected to give your answer to two decimal places, using the diagram below:
Step 2;
Using Pythagoras' theorem, we have that:
[tex]\sin 20^0=\text{ }\frac{12}{x}[/tex]
Making x, the subject of the formulae, we have that:
[tex]x\text{ = }\frac{12}{\sin 20^0}[/tex][tex]x\text{ =}\frac{12}{0.3420}[/tex][tex]\begin{gathered} x\text{ = 35. 0877193} \\ x\text{ }\approx\text{ 35. 09 ( two decimal places)} \end{gathered}[/tex]
CONCLUSION:
The length of x in the triangle = 35. 09 ( two decimal places)
