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The slope of a line and one point on the line are given . Write the equation of the line in slope-intercept form. (Hint: it may be helpful to first write it in point slope form y-y1=m(x-x1) and then convert it to the slope intercept form)

The slope of a line and one point on the line are given Write the equation of the line in slopeintercept form Hint it may be helpful to first write it in point class=

Respuesta :

Using the slope-point formula for the equation of a line we get:

[tex]y-1=-\frac{1}{2}(x-(-4))\text{.}[/tex]

Taking the above equation to its slope-intercept form we get:

[tex]\begin{gathered} y-1=-\frac{1}{2}(x+4), \\ y-1=-\frac{1}{2}x-\frac{4}{2}, \\ y-1=-\frac{1}{2}x-2, \\ y=-\frac{1}{2}x-1. \end{gathered}[/tex]

Answer:

[tex]y=-\frac{1}{2}x-1.[/tex]

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