Given
[tex]\begin{gathered} a=6 \\ n=15 \\ d=4 \end{gathered}[/tex]
It is an arithmetic progression
Solution
[tex]T_n=a_1+(n-1)d[/tex]
Substitute the given into the equation
[tex]\begin{gathered} T_{15}=6+(15-1)4 \\ T_{15}=6+(14)4 \\ T_{15}=6+56 \\ T_{15}=62 \\ \end{gathered}[/tex]
The final answer
Option C
[tex]62seats[/tex]
