So,
Here we have the following inequalities:
[tex]34<3x+7\text{ and }43>3x+7[/tex]
We're going to solve each inequality and then notice which could be the solution set.
Let's begin with:
[tex]\begin{gathered} 34<3x+7 \\ 34-7<3x \\ 27<3x \\ \frac{27}{3}And now, let's solve the other one:[tex]\begin{gathered} 43>3x+7 \\ 43-7>3x \\ 36>3x \\ \frac{36}{3}>x \\ 12>x \end{gathered}[/tex]
Now, what we have to do is to graph both solution sets and find the intersection between them:
As you can notice, both solution sets intersect at the interval (9,12).
So, the solution set is (9,12), which is: 9
If you have to graph it, put:
Which is 9
