Respuesta :
We will convert minutes to seconds for both times. To do that we will use the following conversion factor:
[tex]1\min =60s[/tex]Converting the time for the seventh grade:
[tex]5\min \times\frac{60s}{1\min}=300s[/tex]Therefore, the total number of seconds for the seventh grade is:
[tex]t_7=300s+8s=308s[/tex]Now we convert the time for the eighth grade:
[tex]4\min \times\frac{60s}{1\min}=240s[/tex]The total number of seconds for the eighth grade is:
[tex]t_8=240s+55s=295s[/tex]Now we determine the difference between both times:
[tex]\begin{gathered} d=t_7-t_8 \\ d=308s-295s=13s \end{gathered}[/tex]Therefore, the seventh-grade winner has 13 more seconds.
Another way of solving it is noticing that for 4 min and 55s there is a difference of 5 seconds to be 5 min and to that, we add the 8 seconds of the seventh grade we get:
[tex]5s+8s=13s[/tex]And we get the same answer.
