A ship leaves Port A and travels 66 miles due west to point C. If then adjusts to course 34° northward. It travels 80 miles in that direction until it reaches Port B. What angle 0 with respect to sue north could the ship have used to travel directly from Port A to Port B? See the figure below.

A ship leaves Port A and travels 66 miles due west to point C If then adjusts to course 34 northward It travels 80 miles in that direction until it reaches Port class=

Respuesta :

The figure shows the geometric construction related to the problem.

We need to complete the figure with some extra variables.

The triangle with sides of 80 miles, x, and y is a right triangle. We can apply trigonometric ratios. For example, the sine of 34° is the ratio of the opposite side (y) and the hypotenuse (80), thus:

[tex]sin34\degree=\frac{y}{80}[/tex]

Solving for y:

[tex]y=80sin34\degree[/tex]

We'll leave the calculations for later. Now apply the cosine ratio:

[tex]cos34\degree=\frac{x}{80}[/tex]

Or, equivalently:

[tex]x=80cos34\degree[/tex]

Now focus on the upper triangle (another right triangle) with legs of length x + 66 and y. We can apply the tangent of the unknown angle to find its measure as follows:

[tex]tan\theta=\frac{x+66}{y}[/tex]

Recall the tangent ratio is the ratio between the opposite leg and the adjacent leg.

Substituting the determined values of x and y:

[tex]tan\theta=\frac{80cos34\degree+66}{80sin34\degree}[/tex]

Calculating (we need a scientific calculator):

[tex]\begin{gathered} tan\theta=\frac{66.3230+66}{44.7354} \\ \\ tan\theta=2.9579 \end{gathered}[/tex]

Now calculate the value of the angle with the inverse tangent function:

[tex]\begin{gathered} \theta=arctan(2.9579) \\ \\ \theta=71.3\degree \end{gathered}[/tex]

Answer: 71.3°

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