Answer:
Explanation:
From the given graph, we can see that the vertices of triangle ABC are;
[tex]\begin{gathered} A(4,2) \\ B(4,4) \\ C(-4,1) \end{gathered}[/tex]
To translate 6 units right, we have to add 6 to the x-coordinates of each of the vertices of the triangle and to translate 7 units down, we have to subtract 7 from the y-coordinates of each of the vertices of the triangle as seen below;
[tex]A^{\prime}(4+6,2-7)\rightarrow A^{\prime}(10,-5)[/tex][tex]B^{\prime}(4+6,4-7)\rightarrow B^{\prime}(10,-3)[/tex][tex]C^{\prime}(-4+6,1-7)\rightarrow C^{\prime}(2,-6)[/tex]
Below is the graph of the image of triangle ABC which is triangle A'B'C';
