Answer:
(5 x - 1) (5 x + 1)
Explanation:
If we have an expression of the form
[tex]((ax)^2-1)^{}_{}[/tex]then it can be factored out as
[tex]((ax)^2-1)^{}_{}=(ax-1)(ax+1)[/tex]Now in our case we have
[tex]25x^2-1[/tex]which can be rewritten as
[tex](5x)^2-1[/tex][tex]=(5x-1)(5x+1)[/tex]which is our answer!
