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An observer (O) is located 500 feet from the school (S). The observer notices a bird (B) flying at a 39 degree angle of elevation from his line of sight. How high is the bird flying over the school? Pls show work

Respuesta :

To answer this question we will use the following diagram as a reference:

Recall that in a right triangle we get:

[tex]\tan\theta=\frac{OppositeLeg}{AdjacentLeg}.[/tex]

From the given diagram we get:

[tex]\tan39º=\frac{SB}{OS}=\frac{SB}{500ft.}[/tex]

Therefore:

[tex]SB=500ft\tan39º.[/tex]

Simplifying the above result we get:

[tex]SB\approx404.89ft.[/tex]

Answer: 404.89ft.

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