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Consider this system of linear equations:y = 4/5x - 3y = 4/5x + 1Without graphing, determine how many solutions you would expect this system of equations to have. Explain your reasoning.

Consider this system of linear equationsy 45x 3y 45x 1Without graphing determine how many solutions you would expect this system of equations to have Explain yo class=

Respuesta :

Given:

y = 4/5x - 3

y = 4/5x + 1

Looking at the above equation, they both have the same coefficient of y and also the same slope but there intercepts are different.

If we are to subtract the second equation from the first equation, we will have

0 = -4.

The above statement is incorrect because 0 ≠ 4 .

Hence, we can now say the system of equations has no solutions from the above reasoning.