Answer:
[tex]80\text{ L}[/tex]Explanation:
Here, we want to get the volume of the gas at a reduced pressure
From Boyle's law, we have it the volume and pressure of a given mass of gas are inversely proportional
Mathematically:
[tex]\begin{gathered} P_1V_1\text{ = P}_2V_2 \\ \\ V_2\text{ = }\frac{P_1V_1}{P_2} \end{gathered}[/tex]Where:
P1 is the initial pressure wich is 3800 mmHg
V1 is the initial volume which is 12 L
P2 is the final pressure which is 570 mmHg
V2 is the final volume which is ?
Substituting the values, we have it that:
[tex]\begin{gathered} P_2\text{ = }\frac{3800\times12}{570} \\ \\ P_2\text{ = 80 L} \end{gathered}[/tex]