Respuesta :

[tex]\begin{gathered} 6-\frac{3}{4}x+\frac{1}{3}=\frac{1}{2}x+5 \\ \text{if you use 12 the fraction will be eliminated on both sides} \\ (6-\frac{3}{4}x+\frac{1}{3})12=(\frac{1}{2}x+5)12 \\ 72-9x+4=6x+60 \end{gathered}[/tex]

The answer is D