To answer the question we need to find the volume of each container.
The volume of a cone is given by:
[tex]V=\frac{1}{3}\pi r^2h[/tex]from the figure r=6 and h=12. Plugging this values we have:
[tex]\begin{gathered} V=\frac{1}{3}\pi(6)^2(12) \\ =144\pi \end{gathered}[/tex]The volume of a cylindir is given by:
[tex]V=\pi r^2h[/tex]plugging the values we have:
[tex]\begin{gathered} V=\pi(12^2)(6) \\ =864\pi \end{gathered}[/tex]Now, we notice that the volume of the cylinder is bigger than the cone, to find how much we substract them:
[tex]\begin{gathered} 864\pi-144\pi=720\pi \\ \approx2261.95 \end{gathered}[/tex]Therefore we conclude that:
The volume of the cone is about 2,261.95 cubic centimeter less than the volume of the cylinder. (The answer is option A.)