Answer:
The correct option is D
The function has vertical asymptotes wherever
cos x = 0
Explanation:
Given that
[tex]g(x)=\sec x[/tex]
Note that
[tex]\sec x=\frac{1}{\cos x}[/tex]
This has vertical asymptotes wherever the denominator is zero, that is;
[tex]\cos x=0[/tex]
