ANSWER:
0 J
STEP-BY-STEP EXPLANATION:
Given:
Applied force (F) = 2 N
Friction force (Ff) = -2 N
Distance (d) = 10 m
The work is equivalent to the product between the force and the distance, therefore, we calculate it in the following way:
[tex]\begin{gathered} \text{For the case of the applied force} \\ \\ W_{app}=F\cdot d \\ \\ \text{ We replacing} \\ \\ W_{app}=10\cdot2 \\ \\ W_{app}=20\text{ J} \\ \\ \text{ For the case of the friction force} \\ \\ W_{fric}=F_f\cdot d \\ \\ \text{We replac}\imaginaryI\text{ng} \\ \\ W_{fric}=-10\cdot2 \\ \\ W_{fric}=\text{ -20 J} \\ \\ \text{ Therefore, the total work would be:} \\ \\ W=W_{app}+W_{fric} \\ \\ W=20-20 \\ \\ W=0\text{ J} \end{gathered}[/tex]Which means that the total work is equal to 0 joules
