Given:
[tex]\begin{gathered} 2x-3y=4 \\ \\ 5x+2y=-9 \end{gathered}[/tex]Required:
To calculate the value of x and y
Explanation:
[tex]\begin{gathered} 2x-3y=4 \\ \\ 5x+2y=-9 \\ \\ rearrange\text{ the like terms to the same side of the equation} \\ \\ 2x-3y=4 \\ \\ 2y=-9-5x \\ \\ divide\text{ bpth sides of the equation by the coefficient of variable} \\ \\ y=\frac{-9-5x}{2} \\ \\ substitute\text{ into one of the equation} \end{gathered}[/tex][tex]\begin{gathered} 2x-3\times\frac{-9-5x}{2}=4 \\ \\ solve\text{ the equation } \\ \\ 4x-3(-9-5x)=4\times2 \\ \\ 4x+27=4\times2 \\ \\ 19x+27=8 \\ \\ 19x=8-27 \\ \\ 19x=-19 \\ \\ x=-1 \end{gathered}[/tex][tex]\begin{gathered} substitute\text{ value of x in the equation we get} \\ \\ y=\frac{-9-5\times(-1)}{2} \\ \\ solve\text{ the equation we get} \\ \\ y=-2 \end{gathered}[/tex]Required answer:
X=-1
Y=-2
