Respuesta :

Answer : Option C , ALO2

1. calculate number of moles for Aluminimun ;

given that mass = 3.91 g

Molecular mass =26,98

∴ moles = 3.91 g/26.98

= 0.144 moles

2. Calculate number of moles for Oxygen

given that mass = 3.49 g

Molecular mass =16g/mol

∴ moles = 3.49g/16g/mol

=0.218 moles

3. Divide all components by the smallest value:

• Aluminium : 0.144 /0.144 moles= ,1 mole

,

• Oxygen : 0.218 /0.144 =1.5 moles≈ ,2 moles

Therefore the emperical formula is AlO2

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