First we need to translate the name to the compound.
trioxonitrate means we have 3 oxygens and one nigrogen.
The V means the N is 5+. If each O is 2-, we have a total of 5+ from the N and 6- from the 3 O, so the trioxonitrate(V) has a charge of 1-. Sicne it is acid, the charge is neutralized by H⁺, and since the charge is only 1-, we only need 1 H⁺.
So, the compound is HNO₃. This compound is a strong acid, which means that pratically all of the compounds dissociate in aqueous solution.
[tex]HNO_3\to H^++NO^-_3_{}[/tex]If we have a solution of 0.05 mol/dm³ and each dissociates, we will have the same concentration of H⁺:
[tex]\lbrack H^+\rbrack=0.05mol\/dm^3[/tex]And since dm³ is the same as L, we have:
[tex]\lbrack H^+\rbrack=0.05mol\/L[/tex]The pH can be calculated as:
[tex]pH=-\log _{10}\lbrack H^+\rbrack[/tex]Where [H⁺] is in mol/L, so:
[tex]\begin{gathered} pH=-\log _{10}0.05 \\ pH=-(-1.301\ldots) \\ pH=1.301\ldots \\ pH\approx1.3 \end{gathered}[/tex]So, the pH is approximately 1.3.