Answer:
12n+7
Explanation:
Given the arithmetic sequence
[tex]19,31,43,55[/tex]• The first term, a=19
,• Common difference, d = 31-19 = 12
The nth term of an arithmetic sequence is obtained using the formula:
[tex]U_n=a+(n-1)d[/tex]Substituting the given values, we have:
[tex]\begin{gathered} U_n=19+12(n-1) \\ =19+12n-12 \\ =12n+7 \end{gathered}[/tex]An equation for the nth term is 12n+7.
