We have the next system of equations
[tex]\begin{gathered} 2x+3y=15 \\ x-3y=3 \end{gathered}[/tex]
In order to solve the system of equations by elimination, we need to sum the equations
[tex]2x+x+3y+(-3y)=15+3[/tex]
then we sum like terms
[tex]3x=18[/tex]
then we isolate the x
[tex]x=\frac{18}{3}=6[/tex]
x=6
Then we substitute the value of x in the second equation
[tex]\begin{gathered} x-3y=3 \\ 6-3y=3 \\ \end{gathered}[/tex]
then we isolate the y
[tex]\begin{gathered} -3y=3-6 \\ -3y=-3 \\ y=\frac{-3}{-3} \\ y=1 \end{gathered}[/tex]
The solution of the system of equation is
x=6
y=1
