Answer:
37.6 N
Explanation:
We can represent the situation with the following
Then, the net force is equal to:
[tex]\begin{gathered} F_{net}=T-mg=ma_c \\ \Rightarrow T-mg=m\frac{v^2}{r} \end{gathered}[/tex]Where T is the tension, mg is the weight, m is the mass, v is the speed, and r is the radius of the circular motion of the ball. Solving for T, we get:
[tex]T=m\frac{v^2}{r}+mg[/tex]Now, we can replacing m = 2 kg, v = 3 m/s, r = 1 m, and g = 9.8 m/s²
[tex]\begin{gathered} T=2(\frac{3^2}{1})+2(9.8) \\ T=2(9)+19.6 \\ T=18+19.6 \\ T=37.6 \end{gathered}[/tex]Therefore, the tension in the string at this point is 37.6 N
