You have to translate the triangle ABC using the following translation rule:
[tex](x,y)\to(x-6,y+2)[/tex]
Subtracting 6 to the x-coordinate results in a horizontal translation of 6 units to the left.
Adding 2 to the y-coordinate results in a vertical translation of 2 units up.
To determine the coordinates of A'B'C' you have to subtract 6 units to each x-coordinate and add 2 to each y-coordinate of the vertices of ABC
The coordinate of the vertices are
A(3,1)
B(4,-3)
C(2,-4)
Now you can calculate the translation as follows
A(3,1) → A'(3-6,1+2)=(-3,3)
B(4,-3) → B'(4-6,-3+2)=(-2,-1)
C(2,-4) → C'(2-6,-4+2)=(-4,-2)
