The area of a triangle is computed as follows:
[tex]A=\frac{b\cdot h}{2}[/tex]where b is the base, and h is the height
Replacing with A = 54, h = 18, and solving for b, we get:
[tex]\begin{gathered} 54=\frac{b\cdot18}{2} \\ 54\cdot2=b\cdot18 \\ \frac{108}{18}=b \\ 6=b \end{gathered}[/tex]The base of the triangle is 6 in
