The given figure can be redrawn as,
The area of a rectangle is the product of length and breadth of the rectangle.
Hence, the area of rectangle ABCD is,
[tex]\begin{gathered} \text{Area}_{ABCD}=AB\times AD \\ =2\times6 \\ =12cm^2 \end{gathered}[/tex]
The area of rectangle ECGF is,
[tex]\begin{gathered} \text{Area}_{ECGF}=EF\times FG \\ =4\times7 \\ =28cm^2 \end{gathered}[/tex]
Hence, the total area of the figure is,
[tex]\begin{gathered} \text{Area}=Area_{\text{ABCD}}+Area_{ECGF} \\ =12+28 \\ =40cm^2 \end{gathered}[/tex]
Therefore, the area of the figure is 40 cm^2.
Hence, option (B) is correct
