Respuesta :
Mr. Mangan goes first in the north a distance
[tex]d_1=50\text{ m}[/tex]at time,
[tex]t_1=5\text{ s}[/tex]then towards east ,
[tex]d_2=50\text{ m}[/tex]in time,
[tex]t_2=7\text{ s}[/tex]after that he goes towards south a distance,
[tex]d_3=50\text{ m}[/tex]in time,
[tex]t_3=3\text{ s}[/tex]the average speed is,
[tex]\begin{gathered} s=\frac{total\text{ distance }}{\text{total time}} \\ =\frac{50+50+50}{5+7+3} \\ =10\text{ m/s} \end{gathered}[/tex]The average velocity is,
[tex]v=\frac{displacement}{\text{total time}}[/tex]Here the displacement is,
[tex]d^{\prime}=50\text{ m}[/tex]The average speed is,
[tex]\begin{gathered} v=\frac{50}{5+7+3} \\ =3.33\text{ m/s} \end{gathered}[/tex]The average velocity is,
[tex]v=3.33\text{ m/s along east}[/tex]