Okay, here we have this:
A)
Considering the provided information we are going to replace in the following equation:
[tex]nCr=\frac{n!}{(n-r)!r!}[/tex]Replacing we obtain:
[tex]\begin{gathered} _{12}C_6=\frac{12!}{(12-6)!6!} \\ _{12}C_6=\frac{12!}{6!\cdot\:6!} \\ _{12}C_6=\frac{12\cdot\:11\cdot\:10\cdot\:9\cdot\:8\cdot\:7}{6!} \\ =\frac{665280}{6!} \\ =\frac{665280}{720} \\ =924 \end{gathered}[/tex]Finally we obtain that the number of ways considering that the order of the choices IS relevant is 924.
