The given equation is
[tex]6x^2+x+3=0[/tex]
it is of the from
[tex]ax^2+bx+c=0[/tex]
where a=6 , b=1 and c=3
Consider the quadratic formula
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]
Recall that the discriminant of the quadratic equation is the part of the underneath square root of the formula
[tex]discriminant=b^2-4ac[/tex]
Substitute a=6,b=1 and c=3, we get
[tex]discriminant=1-4\times6\times3=-71<0[/tex][tex]\text{If }discriminant=b^2-4ac<0\text{ then the }quadratic\text{ }equation\text{ has no real solutions.}[/tex]
Discriminant=-71
Hence there is no solution.
