Given:
[tex]4r^2+8r-5[/tex]
Required: To factor the given expression completely.
This is explained thus:
We can factor the quadratic expression as follows:
[tex]\begin{gathered} 4r^{2}+8r-5 \\ 4r^2+10r-2r-5 \\ (4r^2+10r)(-2r-5) \\ 2r(2r+5)-1(2r+5) \\ (2r-1)(2r+5) \end{gathered}[/tex]
Hence, the answer is:
[tex](2r-1)(2r+5)[/tex]
