Part a
Assuming that order is unimportant
we have a combination
17C5
[tex]17C5=\frac{17!}{5!(17-5)!}=6,188[/tex]Probability is
P=0.0001616
P=0.01616%
Part B
Assuming that the order matters
we have a permutation
17P5
[tex]17P5=\frac{17!}{(17-5)!}=742,560[/tex]probability is
P=0.0000013467
P=0.0003467%