To solve this question, follow the steps below.
Part A.
Step 01: Substitute x by 6.
[tex]\begin{gathered} f(x)=3x^2+5x-5 \\ f(6)=3\cdot6^2+5\cdot6-5 \end{gathered}[/tex]
Step 02: Solve the square.
[tex]f(6)=3\cdot36+5\cdot6-5[/tex]
Step 03: Solve the multiplication.
[tex]\begin{gathered} f(6)=3\cdot36+5\cdot6-5 \\ f(6)=108+30-5 \end{gathered}[/tex]
Step 04: Solve addition and subtraction.
[tex]\begin{gathered} f(6)=138-5 \\ f(6)=133 \end{gathered}[/tex]
Answer: f(6) = 133.
Part B.
To find f(-4), follow the same steps as above.
Step 05: Substitute x by -4.
[tex]\begin{gathered} f(x)=3x^2+5x-5 \\ f(-4)=3\cdot(-4)^2+5\cdot(-4)-5 \end{gathered}[/tex]
Step 06: Solve the square.
[tex]f(-4)=3\cdot16+5\cdot(-4)-5[/tex]
Step 07: Solve the multiplication.
[tex]f(-4)=48-20-5[/tex]
Step 08: Solve addition and subtraction.
[tex]\begin{gathered} f(-4)=28-5 \\ f(-4)=23 \end{gathered}[/tex]
Answer: f(-4) = 23.
In summary,
A) f(6) = 133.
B) f(-4) = 23.
