we have
[tex]g(x)=x^2-3x-10[/tex][tex]g\mleft(x+3\mright)=x^2+bx-c[/tex]Solve for b and c
step 1
Find out g(x+3)
[tex]g(x+3)=(x+3)^2-3(x+3)-10[/tex]simplify
[tex]g(x+3)=x^2+6x+9^{}-3x-3-10[/tex]combine like terms
[tex]g(x+3)=x^2+3x-4[/tex]equate with the given expression
[tex]x^2+3x-4=x^2+bx-c[/tex]b=3
c=4
3x=bx -------> b=3
-4=-c ------> c=4
