The rule of the volume of the cone is
[tex]V=\frac{1}{3}\pi r^2h[/tex]
r is the radius of the base
h is the height of the cone
From the picture, we can see
The diameter of the base is 6 feet and the height is 15 feet
Since the radius is half the diameter, then
[tex]\begin{gathered} r=\frac{1}{2}d \\ r=\frac{1}{2}(6) \\ r=3 \end{gathered}[/tex]
Substitute r by 3 and h by 15 to find the volume
[tex]\begin{gathered} V=\frac{1}{3}(\pi)(3)^2(15) \\ V=45\pi\text{ f}eet^3 \end{gathered}[/tex]
The volume of the cone is 45pi feet^3
The answer is A
