A shipping carton has the shape of right triangular prism. Thelength of the carton is 4 times the longer lag of the righttriangular base. The shorter leg of the base is 1/2 of the longerleg. If the volume is 5832 cubic inches what is the length of thecarton?

A shipping carton has the shape of right triangular prism Thelength of the carton is 4 times the longer lag of the righttriangular base The shorter leg of the b class=

Respuesta :

EXPLANATION

Let's see the facts:

Length = 4*longer leg

Shorter leg of the base= 1/2 longer leg

We know that Volume = 5832 = 1/2* length* longer leg* shorter leg

Let's call x to the longer leg, the variables are:

length= 4*longer leg= 4x --> x is the longer leg

Shorter leg= 1/2longer leg= 1/2x --> x is the longer leg

Substituting terms, the equation would be:

[tex]5832=\frac{1}{2}\cdot4x\cdot x\cdot\frac{1}{2}x[/tex]

Multiplying like terms:

[tex]5832=\frac{4}{4}x^3[/tex]

Simplifying:

[tex]5832=x^3[/tex]

Switching sides:

[tex]x^3=5832[/tex]

Isolating x:

[tex]x=\sqrt[3]{5832}[/tex]

Solving the cubic root:

[tex]x=18[/tex]

So, x is the value of the longer leg.

Now, we need to find the length, we know that length=4*longer leg

So, the length of the carton is 4*18= 72

The answer is 72