Object height = 48.45 cm
Explanation:Focal length, f = -15.5 cm
Image distance, v = -13.5 cm
Object distance, u = ?
Relationship between image distance, object distance, and focal length is:
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex][tex]\begin{gathered} \frac{-1}{15.5}=\frac{1}{u}-\frac{1}{13.5} \\ \\ \frac{1}{u}=\frac{1}{13.5}-\frac{1}{15.5} \\ \\ \frac{1}{u}=0.00955794504 \\ \\ u=\frac{1}{0.00955794504} \\ \\ u=104.625\text{ cm} \\ \\ \\ \end{gathered}[/tex]Magnification = |v/u|
[tex]\begin{gathered} M=|\frac{v}{u}| \\ \\ M=|\frac{-13.5}{104.625}| \\ \\ M=0.129 \end{gathered}[/tex]Image height, H = 6.25 cm
Object height, h = ?
[tex]\begin{gathered} M=\frac{H}{h} \\ \\ 0.129=\frac{6.25}{h} \\ \\ h=\frac{6.25}{0.129} \\ \\ h=48.45\text{ cm} \end{gathered}[/tex]Object height = 48.45 cm
