Given data:
The mass of satellite is m=1750 kg.
The gravitational potential enegy of the statellite is GPE=1.69x10¹⁰ J.
The free fall acceleration is g=6.44 m/s².
The expression for the gravitational potential energy of the satellite is given by,
[tex]\text{GPE}=\text{mgh}[/tex]Here, g is the free fall acceleration, and h is the height of satellite above the Earth surface.
Substitute the given values in above equation,
[tex]\begin{gathered} 1.69\times10^{10}=(1750)(6.4)h \\ h=1.49\times10^6\text{ m} \end{gathered}[/tex]Thus, the height of satellite above the Earth surface is 1.49x10⁶ m.
