Respuesta :

To answer this question, we need to use the following equation (point-slope):

[tex]y-y1=m(x-x1)[/tex]

We have:

• m = 6

,

• The point is (-7, 1)

Then

[tex]y-1=6(x-(-7))\Rightarrow y-1=6(x+7)\Rightarrow y-1=6x+42_{}[/tex]

Therefore

[tex]y=6x+42+1\Rightarrow y=6x+43[/tex]

Then the point-slope form of a line with m = 6, passing through (-7,1) is

[tex]y-1=6(x+7)[/tex]

[tex]y=6x+43[/tex]

And the previous result is the standard form of the equation.

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