Solving the quadratic equation, we have:
[tex]\begin{gathered} 3(x-2)^2=12 \\ (x-2)^2=\frac{12}{3} \\ (x-2)^2=4 \\ \sqrt[]{(x-2)^2}=\sqrt[]{4} \\ \begin{cases}x-2=2\to x=4 \\ x-2=-2\to x=0\end{cases} \end{gathered}[/tex]So the solution for this quadratic equation is x = 0 or x = 4.
