4.
The equation we have is:
[tex]\frac{8}{5}a=-6[/tex]
To solve for "a", we want to isolate it in one side.
For this. we can start by multiplying each side by 5. This will make the denominator to cancel out:
[tex]\begin{gathered} 5\cdot\frac{8}{5}a=5\cdot(-6) \\ 8a=-30 \end{gathered}[/tex]
Now, we can divide both sides by 8, which will cancel the coefficient 8 multiplying "a":
[tex]\begin{gathered} \frac{8a}{8}=-\frac{30}{8} \\ a=-\frac{15}{4} \end{gathered}[/tex]
And that is the answer to 4.
