A quadratic function with x-intercepts 7 and 10 has the form (because when x = 10 , y = 0 and x = 7, y = 0)
[tex]y=c(x-10)(x-7)[/tex]where c is a constant hitherto unknown.
We are told that the quadratic function passes through (2, 4) meaning when x = 2 then y = 4. Putting these values into the above equation gives us
[tex]4=c(2-10)(2-7)[/tex][tex]\rightarrow4=40c[/tex][tex]\therefore c=0.1[/tex]Hence, the final form of our quadratic equation is
[tex]y=0.1(x-10)(x-7)[/tex]which is our answer.