Given:
A man is dieting for three weeks
The man loses 5 5/6 pounds the first week, 5 4/5 pounds the second week, and 3 2/3 pounds the third week
So, the sum of the pounds =
[tex]5\frac{5}{6}+5\frac{4}{5}+3\frac{2}{3}=\frac{153}{10}[/tex]So, the average weekly weight loss =
[tex]\frac{153}{10}\div3=\frac{153}{10}\times\frac{1}{3}=\frac{153}{30}=\frac{51}{10}=5\frac{1}{10}[/tex]So, the answer will be:
the average weekly weight loss 5 1/10 pounds
