[tex]\begin{gathered} у=5х-3 \\ 3х-у=-1 \\ 3x-\mleft(5x-3\mright)=-1 \\ 3x-5x+3=-1 \\ -2x+3=-1 \\ -2x+3-3=-1-3 \\ -2x=-4 \\ \frac{-2x}{-2}=\frac{-4}{-2} \\ x=2 \end{gathered}[/tex]
then solve for y
[tex]\begin{gathered} y=5\cdot\: 2-3 \\ y=10-3 \\ y=7 \end{gathered}[/tex]
answer
x = 2
y = 7
