Given:
[tex]x^2-10x-3=0[/tex]Find the solution.
Sol:
Use quadratic formula then,
[tex]\begin{gathered} ax^2+bx+c=0 \\ \\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \end{gathered}[/tex]Apply the formula is:
[tex]\begin{gathered} x^2-10x-3=0 \\ \\ x=\frac{-(-10)\pm\sqrt{(-10)^2-4(1)(-3)}}{2(1)} \\ \\ x=\frac{10\pm\sqrt{100+12}}{2} \\ \\ x=\frac{10\pm\sqrt{112}}{2} \end{gathered}[/tex]So the value of x is:
[tex]\begin{gathered} x=\frac{10\pm\sqrt{112}}{2} \\ \\ x=\frac{10\pm\sqrt{28\times4}}{2} \\ \\ x=\frac{2(5\pm\sqrt{28})}{2} \\ \\ x=5\pm\sqrt{28} \\ \\ x=5\pm5.29 \\ \\ x=0.29,x=10.29 \end{gathered}[/tex]So the value of "x" is 0.3 and 10.3
