[tex]\begin{gathered} f(x)=\text{ }\sqrt[]{x} \\ h(x)\text{ is shifted to the left of f(x) for which } \\ x\text{ =-5 } \\ \text{then x + 5 = 0} \end{gathered}[/tex]
we can replace x in f(x) with x + 5
so that
h(x) =
[tex]\begin{gathered} h(x)\text{ = }\sqrt[]{x\text{ + 5}} \\ \end{gathered}[/tex]