[tex]\ln (e^{-9}e^8)=-1[/tex]
Explanation
Step 1
remember some properties of the potentiation
[tex]\begin{gathered} a^m\cdot a^n=a^{m+n} \\ \end{gathered}[/tex]
then
[tex]e^{-9}\cdot e^8=e^{-9+8}=e^{-1}[/tex]
Now we have
[tex]\ln (e^{-9}e^8)=\ln (e^{-1})[/tex]
Step 2
using some properties of ln
[tex]\begin{gathered} \ln (e^{-1})=-1\cdot\ln (e^{}) \\ and\text{ }\ln (e^{})=1,then \\ \ln (e^{-1})=-1\cdot1 \\ \ln (e^{-1})=-1 \\ \ln (e^{-9}e^8)=-1 \end{gathered}[/tex]
I hope this helps you
