We solve as follows:
[tex]x=\frac{-(-24)\pm\sqrt[]{(-24)^2-4(4)(0)}}{2(4)}[/tex]Then:
[tex]\begin{gathered} x=0 \\ x=6 \end{gathered}[/tex]As we can see the function:
[tex]4x^2-24x[/tex]Is of the form:
[tex]ax^2+bx+c[/tex]Where a = 4, b = -24 & c = 0
Since it follows that form, we can solve it using the quadratic function:
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]When we solve it gives us that x = 0 and x = 6 when we equal to 0.
