Answer:
F = 0.45 N
Explanation:
The magnitude of the force on the wire can be calculated as:
[tex]F=I\cdot L\cdot B\cdot\sin \theta[/tex]Where I is current, L is the length of the wire, B is the magnetic field and θ is the angle formed by the wire and the magnetic field.
Since they are at a right angle, θ = 90 degrees. So, replacing I = 6.0A, L = 0.25 m = 25 cm and B = 0.30 T, we get:
[tex]\begin{gathered} F=(6.0A)(0.25m)(0.30T)\sin 90 \\ F=0.45\text{ N} \end{gathered}[/tex]Therefore, the magnitude of the force on the wire is 0.45 N.
